x^2+40x-11700=0

Solution for x^2+40x-11700=0 equation:

x^2+40x-11700=0

a = 1; b = 40; c = -11700;
Δ = b2-4ac
Δ = 402-4·1·(-11700)
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{48400}=220$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-220}{2*1}=\frac{-260}{2}
=-130
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+220}{2*1}=\frac{180}{2}
=90
$